The 2nd London Chess Classic starts at Olympia on Wednesday with the main attraction being the 8-man, invitation-only Classic section, which comprises an equal mixture of four top world players and four top English players. These are the World Champion Vishy Anand of India; World No. 2 Magnus Carlsen, of Norway; ex-world champion Vladimir Kramnik of Russia and US No. 1 Hiraku Nakamura. The English contingent is led by Mickey Adams of Cornwall, followed by Nigel Short, Luke McShane and David Howell. With a prize fund of 145,000 euros at stake, they will certainly be fighting for every half point.
There is local interest, too, among the 119 entrants in the Open Section. 15th seed is Grandmaster Keith Arkell, currently resident in Paignton, while at 31 is Jack Rudd of Bideford. 10 year old Theo Slade of Marhamchurch nr. Bude, has entered one of the weekend sections.
Last year’s Brilliancy Prize was awarded for this win in Rd. 5.
White: H. Nakamura. Black: L. McShane.
King’s Indian Defence [E94]
1.d4 Nf6 2.c4 g6 3.Nc3 Bg7 4.e4 d6 5.Be2 0–0 6.Nf3 e5 7.0–0 Na6 8.Be3 Ng4 9.Bg5 Qe8 10.c5 exd4 11.Nd5 Be6 If Black took the proffered pawn 11…Qxe4 the queen would be harassed as other white pieces join the fray: e.g. 12.Ne7+ Kh8 13.Bd3 Qe6 14.Re1 etc. The text, however, allows a rook to become trapped. 12.Be7 Bxd5 13.Bxf8 Qxf8 14.exd5 dxc5 White emerges from this skirmish the exchange down, but with 5 pawns vs 3 on the queenside, the decisive factor in the end. 15.Qb3 Rb8 16.Rfe1 Qd6 17.h3 Nf6 18.Bxa6 Qxa6 19.Rac1 Bf8 20.Ne5 Qb6 21.Qf3 Qd6 22.g4 Bh6 23.Rc2 Re8 24.Rce2 Rf8 25.Nc4 Qxd5 26.Qxf6 Bg7 27.Qh4 Qxc4 Now it’s 2v5 pawns 28.Re8 Qd5 29.Rxf8+ Bxf8 30.Re8 Kg7 31.g5 Qd6 The bishop will need defending in case White plays 32.Qh5+. With the Kingside stabilised, attention switches to the opposite wing. 32.Kf1 b5 33.Ke1 c4 34.Qe4 c5 35.h4 c3 36.bxc3 dxc3 37.Qe5+ Qxe5+ 38.Rxe5 a5 39.Kd1 a4 40.a3 b4 41.Kc2 h6 42.Rd5 hxg5 43.hxg5 Kh7 44.Rd7 Bg7 45.Rxf7 b3+ 46.Kb1 Kg8 47.Ra7 Bd4 48.Rxa4 Kf7 49.Ra6 Be5 50.Ra4 Ke6 51.Rh4 Kd5 52.a4 c4 53.Rh1 c2+ 54.Kc1 c3 55.Rh4 White has to counter the threat of Bf4 mate but cannot cope with the other threat. 55…Bd6 0–1
The solution to last week’s 2-mover by the problem pioneer, John Brown of Bridport, was 1.Bf4! after which White has seven different mates, depending on how Black tries to defend.
Here is another early 2-move teaser by the Hungarian Moritz Ehrenstein (1858-1923).